How to Calculate Current in a Solenoid with Given Field and Dimensions?

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To calculate the current in a solenoid producing a magnetic field of 0.215 T, the relevant formula is B = μIN / l, where B is the magnetic field, μ is the permeability of free space, I is the current, N is the number of turns, and l is the length of the solenoid. Given a solenoid length of 0.27 m, a diameter of 1.25 cm, and 900 turns, the diameter is not necessary for the calculation of current. The confusion arises from the inclusion of the diameter, which does not affect the magnetic field at the center. Ultimately, the key focus is on using the length and number of turns to determine the required current. Understanding the parameters correctly is essential for solving the problem accurately.
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Homework Statement



A 27.0-cm long solenoid 1.25 cm in diameter is to produce a field of 0.215 T at its center. How much current should the solenoid carry if it has 900 turns of the wire?

Homework Equations



B = μIN / l

The Attempt at a Solution



Why am I given the diameter plus the length? Everything else is obvious except this concept. I thought l would equal = 0.27 m. Should I add 0.625 + 0.27 m because the magnetic field is produced at the center?
 
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you don't need the diameter at all for this problem ;)
 
Aha! Extra information! Thank you.
 
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