How to Calculate Delta G and Keq for Chemistry Test?

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To calculate the ratio of AB to A at equilibrium, use the equation K_eq = [AB]/([A][B]), applying the given values to find the ratio as 0.05:1. For Delta G of the reaction x <-> y, the formula is Delta G = -RT ln(K_eq), where R is the gas constant and T is the temperature in Kelvin. Substituting the provided values into this formula yields a Delta G of -1.18 kcal/mol. It's essential to reference your chemistry texts for detailed equations and constants. Understanding these calculations is crucial for success in chemistry tests.
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I got these two questions i have no idea how to do (i have answers, but no soln's)
1. Given that the affinity constatn Keq for rxn A+B=AB is 5x10^6 and the concentration of free molecules at equillibrium are Afree = 1x10^-4 and B = 1x10^-8, what is the ration of AB to A at equillibrium

ans: 0.05 : 1

2. What is the Delta G for the forward reaction x <-> y.
Given
R = 1.98x10^-3 kcal/molK
T = 298K
K'eq = 7.5

(ans: -1.18kcal/mol)
 
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Read this before posting :

https://www.physicsforums.com/showthread.php?t=4825
 
Use K_{eq} = \frac{[AB]}{[A]<b>} </b>
 
Gokul43201 said:
Read this before posting :

https://www.physicsforums.com/showthread.php?t=4825
you don't understant.. its not my hw. just tell me the formula for delta g, that's all i need
 
K= \frac{[x]}{[A-x][B-x]}

You should be able to find such equations in the text by yourself, the're all listed explicitly.

...since it's urgent
 

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