How to Calculate Horizontal Jumping Speed on a Skateboard?

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To calculate horizontal jumping speed on a skateboard, one must apply the conservation of momentum principle. The initial momentum is determined by the combined mass of the skateboarder and the skateboard multiplied by their initial velocity. When the skateboarder jumps off, the momentum is redistributed between the skateboarder and the skateboard. For example, a 65kg skateboarder and a 5kg skateboard at 10m/s results in the skateboarder achieving a speed of approximately 10.76m/s after the jump. Understanding these calculations is crucial for accurately determining the skateboarder's horizontal speed upon jumping.
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if someone was standing on a skateboard at rest and then jumped off, how would you calculate the person's horizontal jumping speed (if the skateboard rolled in the opposite direction). what information would i need? (the masses of the person and the skateboard and the speed which the skateboard went?)
thanks for any help!
 
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Conservation of momentum - (total mass of skateboarder + board) * velocity = velocity of skateboarder * his mass + velocity of board + its mass.

For instance, 65kg boarder, 5kg board, initially at 10m/s. Initial momentum = (65+5)kg*10m/s = 700kgm/s. Then assume the board stopped completely - 65kg boarder now takes on all the momentum, his speed will be 700kgm/s divided by 65kg - approx 10.76m/s.

On the other hand, unseatbelted dude and car - momentum = 60kg + 1000kg * 30m/s = 82400kgm/s. The car barely has to slow down to kill said dude.
 

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