How to Calculate Image Position and Magnification for a Camera Lens?

AI Thread Summary
To calculate the image position and magnification for a camera lens with a focal length of 55mm and an object distance of 500mm, the lens formula 1/u + 1/v = 1/f is applied. Substituting the values, the image distance (v) is found to be approximately 62mm. The magnification (m) is calculated as the ratio of image distance to object distance, resulting in 0.124. However, it is noted that magnification should be negative, indicating the image is inverted, thus m = -0.124. The calculations and approach taken are confirmed to be correct.
GoodOldLimbo
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Homework Statement



A camera lens has focal length 55mm and an object is 500mm away. Calculate the position of the image and the magnification (or reduction)


Homework Equations



1/u + 1/v = 1/f

u = Object Distance

v = Image Distance

f = focal length

m = magnification

The Attempt at a Solution



f = 55

u = 500

1/500 + 1/v = 1/55

1/55 - 1/500 = 1/v

55-1 - 500 -1 = 0.01618

ANS-1 = 61.79 so approximately 62mm

v/u = m

62/500 = 0.124M

Did I go with the right approach? Any help would be great.
 
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Looks OK to me.

The only things I can think of is that the magnification M = -0.124

1) magnification is supposed to be -ve because the image is usually upside down after the light rays go through a lens provided the object is outside the focal length

2) 0.124M should just be 0.124 since it is a dimensionless number.
 
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