How to calculate pressure of a mixture of oil Reservoir fuids?

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To calculate the pressure of a mixture of oil reservoir fluids, the pressure at the water-oil contact (WOC) is determined using the formula P = ρgh, resulting in a pressure of 64.7 MPa. The heights of the fluid columns are 800 ft for water, 500 ft for oil, and 600 ft for gas. For calculating pressure at the gas-oil contact (GOC) and at depths of 12,500 ft, 11,700 ft, and 11,000 ft, the appropriate height for the water column must be adjusted based on the depth above the WOC. The discussion seeks clarification on whether the water column height should be calculated as 12,000 ft minus the height of the oil column. Accurate pressure calculations are essential for reservoir management and development.
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1. An oil reservoir with normal reservoir pressure at water oil contact (WOC of =12000ft) contains water, oil and gas columns of 800, 500 and 600 ft height respectively.

Calculate reservoir pressure at WOC, gas oil contact (G0C) and depths of 12500, 11700 and 11000 ft?

ρw = 1000 kg/m^3
ρo = 800 kg/m^3
ρg = 120 kg/m^3

g = 9.8 m/s^2
ft = 0.305m
Patm = 0.1 Mpa

2. P = ρgh
3.Would Pressure at WOC be : Patm + Pw + Po = 0.1x10^6 + (1000*9.8*3660m) + (800*9.8*3660m) = 64.7 Mpa

Also what would be the height to use in the P = ρgh formula for the pressure calculations at GOC,depths of 12500, 11700 and 11000 ft.
Would for example the water contact give a height of 12000 - 800 = 11200ft water column?
 
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