How to Calculate Tension in a Rope on an Inclined Surface with Two Unknowns

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To calculate the tension in a rope pulling a 20kg toboggan up a 15-degree incline with the rope at a 30-degree angle, one must analyze the forces acting on the toboggan. The tension must be greater than 52.5N because it needs to counteract the component of the toboggan's weight acting down the slope, which is influenced by the incline and the angle of the rope. Ignoring friction simplifies the calculation, allowing for a focus on the gravitational forces and tension components. A free body diagram is recommended to visualize the forces and their components parallel to the incline. Ultimately, understanding the relationship between these forces is key to determining the required tension.
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dear reader

i have this query which i have not been able to tackle, even after many attempts. i have also consulted my teacher but to no avail. (by the way, this is not actually homework, just work i decided to do).

a toboggan of mass 20kg is pulled, with rope, up a snow-covered hill inclined at 15deg to the horizontal. the rope is inclined at 30 deg to the horizontal. explain why the tension in the rope must certainly be greater than 52.5N. could you please show step-by-step instructions with an answer preferably, just so i know how to apply this technique in the future. thank you
 
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Our policy here is for you to do the work! But we'll be glad to help.

Hint: Consider the forces parallel to the hill. Include the components of rope tension and the toboggan's weight. (I assume there is no friction.)

Give it a try. (Why do you say "two unknowns" in the title?)
 
With problems like this I always make my coordinate system parallel with the incline. For me that seems to help. Perhaps you too.

Draw a free body diagram before you do anything. Like DocAl mentioned, there are not two unknowns in this problem.
 
there is friction, which is why i don't know how to work it out (friction is unknown)
 
have drawn the diagram, but didnt really help
 
bob4000 said:
there is friction, which is why i don't know how to work it out (friction is unknown)
Well you can always ignore the friction. See what the minimum tension is without friction... maybe that's all you need. (Friction will just add to the tension.)

So... ignoring friction, what forces act on the toboggan? And what are the components parallel to the slope?
 
thanks to all who contributed. keep up the good work
 
If my FBD is correct, the force required without friction is higher than the limit posted.

You didn't mention anything about friction in the original question!
 
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