How to Calculate the Amplitude of a Resultant Electromagnetic Wave?

AI Thread Summary
To calculate the amplitude of the resultant electromagnetic wave from two coherent waves, E1 and E2, expressed as E_1=E_o sin(ωt - kx) and E_2=E_o sin(ωt - k(x + δ)), one can use the sine addition formulas. The resultant wave can be represented as a single wave with the same angular frequency and wavenumber, leading to the equation E_o sin(ωt - kx) + E_o sin(ωt - k(x + δ)) = A sin(ωt - k(x + α)). The amplitude A and phase constant α can be derived using the sine difference identity. Understanding this process is crucial for finding A in terms of E0 and δ.
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Homework Statement



The electric components E1 and E2 of two coherent electromagnetic waves are given as follows :

E_1=E_o\sin (\omega t-kx)

E_2=E_o\sin (\omega t-k(x+\delta))

These two waves superpose each other at a certain point . Derive the amplitude of the resultant wave in terms of k and delta .

Homework Equations





The Attempt at a Solution



I tried adding them using the sin formulas , but i failed to express it in the form of

A \cos \theta \sin \omega t
 
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The sum of the two waves can be substituted by a single one of the same angular frequency w and wavenumber k, that is

<br /> E_o\sin (\omega t-kx)+E_o\sin (\omega t-k(x+\delta))= A\sin (\omega t-k(x+\alpha))<br />.

You have to find the expression of A in terms of E0 and delta.

ehild
 
ehild said:
The sum of the two waves can be substituted by a single one of the same angular frequency w and wavenumber k, that is

<br /> E_o\sin (\omega t-kx)+E_o\sin (\omega t-k(x+\delta))= A\sin (\omega t-k(x+\alpha))<br />.

You have to find the expression of A in terms of E0 and delta.

ehild

thanks ehild , but i don really get it , i don see where is the alpha coming from ..
 
Alpha is a phase constant for the new wave. You can determine both alpha and the amplitude A by using the identity for the sine of the difference of angles. Have you learned how to do it?

ehild
 
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