How to Calculate the atomic mass of this isotope?

AI Thread Summary
To calculate the atomic mass of the unknown isotope with a given mass of 2.18 x 10^-22g per atom, one must understand the relationship between atomic mass units (amu) and grams per mole (g/mol). The discussion emphasizes setting up an equation to solve for the atomic mass, denoted as "x." Since one mole of atoms contains approximately 6.022 x 10^23 atoms, the atomic mass can be derived by multiplying the mass of a single atom by Avogadro's number. This approach allows for the conversion from the mass of an individual atom to the atomic mass in amu or g/mol. The key takeaway is the importance of using the correct conversion factors and equations to find the atomic mass.
miiizpiiink18
Messages
9
Reaction score
0
Q: The actual mass of one atom of an unknown isotope is 2.18 x 10^-22g. Calculate the atomic mass of this isotope.

`How do I calculate it? help =]
 
Physics news on Phys.org
Do you know what amu is?

--
 
Borek said:
Do you know what amu is?


or g/mol
 
yes, i know amu and g/mol
 
miiizpiiink18 said:
yes, i know amu and g/mol



so 1 mol would equal whatever the atomic mass of this isotope is... you're given a sample of the isotope...

think about how you would set up an equation to solve for "x" (x, in this case being the atomic mass)
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
Back
Top