How to Calculate the Image Height in a Converging Mirror Problem?

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To calculate the height of the image formed by a converging mirror, the user applied the mirror formula and derived a negative image height of -0.32 cm, which suggests an inverted image. However, the negative sign indicates inversion, while the image should be upright since the object is in front of the mirror. The calculations for the focal length and distances seem correct, but the user may need to reassess the sign convention used for the height of the image. Additionally, there is a separate question about interference patterns, which requires further clarification from a teacher or textbook. Overall, the user is encouraged to review their calculations for accuracy.
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Help would be appreciated...

Hey all,
Grade 11 physics assignment due tmrw and I am having some trouble. Any help would be appreciated. So here it is:

A candle of height 4.8 cm is placed 38.6 cm in front of a converging mirror with curvature 30.2 cm. What is the height of the image?

Heres what I have:

1/f = 1/Di + 1/ Do so... 1/15.1 = 1/Di + 1/38.6 so Di=2.56

then...

Hi/Ho = -Di/Do so... Hi/4.8 = -2.56/38.6 so Hi=-.32

where:
Ho= Height of object (candle)
Do= Distance of object
Di= Distance of image
Hi= Height of image
f=focus (which i have calculated to be 15.1)

The answer i get is -.32cm which doesn't seem right to me. Am i doing something wrong? Missing something??

As well... a totally unrelated question- When looking at interference patterns of water through 2 openings, if the second nodal line is formed at an angle of 50 degrees, will n=1 or n=1/2?

Thanks for any help!
 
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1/15.1 = 1/Di + 1/38.6 so Di=2.56 - you sure that's right?
 


Hi there,

I'm not an expert in physics, but I'll try my best to help. It looks like you have the right equations and have plugged in the values correctly. However, I noticed that you have a negative sign in your equation for Hi. This could be why you are getting a negative value for the height of the image. Remember, the negative sign indicates that the image is inverted, but in this case, the image should be upright since the object is placed in front of a converging mirror. So, you may want to double check your calculations and remove the negative sign if necessary.

Regarding your second question about interference patterns, I'm not sure about the answer. It would be best to double check with your teacher or refer to your textbook for the correct formula and values to use in this situation. I'm sorry I couldn't be of more help with that.

Good luck with your assignment! I hope you are able to figure out the correct answer for the height of the image. Keep trying and don't hesitate to ask for help if you need it. You got this!
 
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