How to calculate this probability (conditional distributions)

Drao92
Messages
70
Reaction score
0
fXY(x,y)=2 if 0<x<1 and x<y<1, 0 for other intervals
I have to calculate: P((x>0.5)π(y<0.5)).
I think it 0 but I am not sure because in all other exercises I've made the surfaces intersect each other. Like in fig 1 for P((x<0.5))π(y<0.5))=integral from 0 to 0.5 from integral from x to 0.5 from 2dydx.
The fig 2 is for P((x>0.5)π(y<0.5)).
Im sorry because i forgot to mark the axis. vertical is y and horizontal is x.I apologize.
https://www.physicsforums.com/attachment.php?attachmentid=58161&stc=1&d=1366802927
https://www.physicsforums.com/attachment.php?attachmentid=58162&stc=1&d=1366802927
 

Attachments

  • fig1.png
    fig1.png
    962 bytes · Views: 759
  • fig2.png
    fig2.png
    998 bytes · Views: 739
Physics news on Phys.org
If I understand your description, the density function = 0 for x > y. Therefore P((x > 0.5) and (y < 0.5)) = 0.
 
Hi all, I've been a roulette player for more than 10 years (although I took time off here and there) and it's only now that I'm trying to understand the physics of the game. Basically my strategy in roulette is to divide the wheel roughly into two halves (let's call them A and B). My theory is that in roulette there will invariably be variance. In other words, if A comes up 5 times in a row, B will be due to come up soon. However I have been proven wrong many times, and I have seen some...
Thread 'Detail of Diagonalization Lemma'
The following is more or less taken from page 6 of C. Smorynski's "Self-Reference and Modal Logic". (Springer, 1985) (I couldn't get raised brackets to indicate codification (Gödel numbering), so I use a box. The overline is assigning a name. The detail I would like clarification on is in the second step in the last line, where we have an m-overlined, and we substitute the expression for m. Are we saying that the name of a coded term is the same as the coded term? Thanks in advance.
Back
Top