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cyberdx16
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Time Dilation help please
A spaceship is moving at 0.75 c (0.75 times the speed of light) with respect to the earth. An observer on the spaceship measures the time interval between two events on Earth as 38 hrs. If the spaceship had been moving with a speed of 0.92 c with respect to the earth, what would the time interval between the events have been?
Δt0.92 c = _____hrs
Δt=Δtp/sqrt1-v^2/c^2
v=.75(3e8)=2.25e8m/s
t=1/368e5sec
v=d/t
d=3.078e13m
Δtp=3.078e13/v
v=.92(3e8)=2.76e8
Δtp=3.078e13/2.76e8
=1.115e5sec
=30.97hr
but this is not the correct ans
Homework Statement
A spaceship is moving at 0.75 c (0.75 times the speed of light) with respect to the earth. An observer on the spaceship measures the time interval between two events on Earth as 38 hrs. If the spaceship had been moving with a speed of 0.92 c with respect to the earth, what would the time interval between the events have been?
Δt0.92 c = _____hrs
Homework Equations
Δt=Δtp/sqrt1-v^2/c^2
The Attempt at a Solution
v=.75(3e8)=2.25e8m/s
t=1/368e5sec
v=d/t
d=3.078e13m
Δtp=3.078e13/v
v=.92(3e8)=2.76e8
Δtp=3.078e13/2.76e8
=1.115e5sec
=30.97hr
but this is not the correct ans