How to Calculate ZIR for a Given Differential Equation?

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To calculate ZIR(t) for the given differential equation, the initial condition y(0-) = 5 must be applied. The equation to solve is 2y' + 3y = 0, leading to the homogeneous solution. For the zero state response, the equation becomes 2y' + 3y = 2x' + x(t-1). The complete response is the sum of the zero input response and the zero state response. This approach ensures the correct calculation of ZIR for the system.
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Homework Statement


Calculate ZIR(t) for the system described for the following differential equation, where the initial condition is y(0-) = 5:


Homework Equations


2y' + 3y = 2x' + x(t-1)


The Attempt at a Solution


I'm pretty sure we're supposed to laplace-transform it, then find Y/X = H(s) then inverse back to time domain.
2*(s*Y - 5) + 4*Y = 2*(s*X) + X*exp(-s)
cannot be solved for Y/X, which makes me think I somehow messeed up the initial transform, or perhaps the method altogether
 
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MooseBoys said:

Homework Statement


Calculate ZIR(t) for the system described for the following differential equation, where the initial condition is y(0-) = 5:


Homework Equations


2y' + 3y = 2x' + x(t-1)


The Attempt at a Solution


I'm pretty sure we're supposed to laplace-transform it, then find Y/X = H(s) then inverse back to time domain.
2*(s*Y - 5) + 4*Y = 2*(s*X) + X*exp(-s)
cannot be solved for Y/X, which makes me think I somehow messeed up the initial transform, or perhaps the method altogether
For the ZIR you must have no imput. So, you must solve
2y´ + 3 y = 0 with y(0) = 5
For the zero state response you solve
2y´ + 3y = 2x´+ x(t-1)
The complete response is the sum of the two.
 
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