How to check this type of weld group?

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To check the weld group, the user suggests calculating the maximum weld stress by first moving the forces Ft and Fl to the geometric center to determine tension and shear stress. They propose using the equation for torsion, T = Ft*Lt + Fl*Ll, to find stress σ = T/(Ix + Iy)*r, and then distributing this result in the x and y directions to obtain equivalent stress. The user seeks confirmation on the accuracy of this method. Additionally, they reference AISC rules for further information on weld group checks. The discussion emphasizes the importance of proper calculations in assessing weld integrity.
atlas_2010
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Hello all,

I am not very sure with this kind of weld check, could you give me some help and suggestion?
Details as following:

Given:
Ft=force in y direction
Lt=distance between Ft action point and weld group geometric center(y direction)
Fl=force in x direction
Ll=distance between Fl action point and weld group geometric center(x direction)
L1=weld 1 length
L2=weld 2 length
L3=weld 3 length
t=weld throat
Ix-=moment interia about x axial
Iy-=moment interia about y axial
r=the max distance form center

Soluation
find out the max weld stress
My solution is this,
First move Ft and Fl to the geometric center get the tension and shear stress
Then take tousionT=Ft*Lt+Fl*Ll(or Ft*Lt-Fl*Ll) take the
stress σ=T/(Ix+Iy)*r,and distribute the result to x and y direction,
and finally get eqivualent stress

Am I right?

Thank you for your help and suggestion.
 

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atlas_2010 said:
Hello all,

I am not very sure with this kind of weld check, could you give me some help and suggestion?
Details as following:

Given:
Ft=force in y direction
Lt=distance between Ft action point and weld group geometric center(y direction)
Fl=force in x direction
Ll=distance between Fl action point and weld group geometric center(x direction)
L1=weld 1 length
L2=weld 2 length
L3=weld 3 length
t=weld throat
Ix-=moment interia about x axial
Iy-=moment interia about y axial
r=the max distance form center

Soluation
find out the max weld stress
My solution is this,
First move Ft and Fl to the geometric center get the tension and shear stress
Then take tousionT=Ft*Lt+Fl*Ll(or Ft*Lt-Fl*Ll) take the
stress σ=T/(Ix+Iy)*r,and distribute the result to x and y direction,
and finally get eqivualent stress

Am I right?

Thank you for your help and suggestion.
Hello all,
I found some information in AISC rules,sorry for cann't upload all documents, for detail information please go through the AISC website or contract me.
https://www.aisc.org/search.aspx?id=3852&keyword=weld group
 

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