per.sundqvist
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We know that we can create an electron-positron pair out of a gamma-ray, if it has an energy of E=h\nu>2m_ec^2.
However a photon is described as an EM-wave that obeys the divergence criteria
\nabla\cdot\vec{E}=0
My question is simply if there is a "simple" explanation out there (QFT?) which describes microscopically what happens when the photon breaks up and 2 charged packages are created? I also wonder what the distance between the particles is in the creation moment.
My guess is that the EM-wave/photon must be disturbed in some way (by gravity?) such that it bends in some way, and that it is this bending which gives rise to the charge creation: \nabla\cdot\vec{E}=\rho/\epsilon, but where the total charge is neutral, like in the point-particle classical situation:
\rho=e(\delta(r-a)-\delta(r+a)) (some kind of dipole, but perhaps rater described with waves)
Any idea?
However a photon is described as an EM-wave that obeys the divergence criteria
\nabla\cdot\vec{E}=0
My question is simply if there is a "simple" explanation out there (QFT?) which describes microscopically what happens when the photon breaks up and 2 charged packages are created? I also wonder what the distance between the particles is in the creation moment.
My guess is that the EM-wave/photon must be disturbed in some way (by gravity?) such that it bends in some way, and that it is this bending which gives rise to the charge creation: \nabla\cdot\vec{E}=\rho/\epsilon, but where the total charge is neutral, like in the point-particle classical situation:
\rho=e(\delta(r-a)-\delta(r+a)) (some kind of dipole, but perhaps rater described with waves)
Any idea?