How to determine change in area of matrices tranformations.

AI Thread Summary
The discussion focuses on determining the change in area of a square under various matrix transformations. The original square has vertices at (0,0), (0,1), (1,1), and (1,0), with an area of 1. Participants suggest using the vector cross product to find the area of the resulting parallelogram after transformation, as it directly relates to area calculations. There is a mention of using trigonometry, but the cross product is recommended for simplicity. Understanding how to apply these concepts is crucial for determining the change in area effectively.
Cacophony
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Homework Statement


Determine what the tranformation does to the square with vertices (0,0), (0,1), (1,1) and (1,0). Draw the image of the square under these tranformations. Then find the change in area of the square under these transformations.

a)
[1 1]
[1 2]

b)
[0 -1]
[2 -1]

c)
[4 1/4]
[3 1/3]
2. Homework Equations [/b]



The Attempt at a Solution


I've plotted out all of the matrices on a graph but i don't understand how to find the change in area. How do I find the change in area?
 
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The vertices (0,0), (0,1), (1,1) and (1,0) make a square of area 1. If you plotted the image they map to you should get some kind of parallelogram in each case. You can use trig to find its area, but it's probably easiest if you know how the vector cross product is related to area.
 
Still not really getting it. I have been out of school for a while so I need a refresher on how to use trigonometry to find the change in area. What does change in area even mean in this case?
 
Cacophony said:
Still not really getting it. I have been out of school for a while so I need a refresher on how to use trigonometry to find the change in area. What does change in area even mean in this case?

You don't have to use trig if it's not fresh in you mind. Look at the vector cross product first. The cross product of two vectors is related to the area of the parallelogram that they span. Look it up.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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