How to Determine Temperature of Heat and Cold Reservoirs in a Carnot Cycle?

AI Thread Summary
To determine the temperatures of the heat and cold reservoirs in a Carnot cycle with a 90-degree Celsius differential and 28% efficiency, one can use the efficiency formula: Efficiency = 1 - (Q_out/Q_in). The 90-degree difference indicates that if the temperature of the cold reservoir is T_c, then the hot reservoir is T_c + 90. To find the specific temperatures, rearranging the efficiency equation in terms of T_c and T_hot can simplify the calculations. Ultimately, expressing Carnot efficiency in terms of the temperatures of the reservoirs is essential for solving the problem effectively.
eliassiguenza
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Homework Statement


All i want to know is how do i find the temperature of my heat and cold reservoir, given that they have a 90 degree celsius/kelvin differential and a 28% efficency.


Homework Equations


Efficency= Work out/ Work in = 1- Q out/Q in


The Attempt at a Solution


I been thinking all night and couldn't sleep well over this, i know how to get efficency but it seems a tricky question, how ever i was thinking of just calculating the heat and work for many diferent temperatures with 90 degrees differential and then see what happens?
Anyone has a better idea? I feel very reluctant of making so many calculations...
 
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How else does one express the carnot efficiency in terms of the temperatures of the hot and cold reservoirs?

They told you that T(hot)-T(cold) = 90.
 
yeah! got that one thank you very much! I thought about it straight away after posting it! thanx
 

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