How to do Mesh Analysis with current controlled voltage source

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The discussion focuses on mesh analysis involving a current-controlled voltage source with a given voltage source equation. The initial mesh equations presented were found to be incorrect due to the omission of a term for the potential drop across the inductor. After correcting the equations, the calculated mesh currents were I1 and I2, leading to a voltage across the inductor that differed significantly from the nodal analysis results. The discrepancy between the mesh and nodal analysis results highlights the importance of accurately accounting for all components in mesh equations. The conversation emphasizes the need for careful application of KVL and KCL in circuit analysis.
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Homework Statement


Vs = 100cos(2000t)
upload_2016-11-7_21-11-57.png


Homework Equations


KVL, KCL

The Attempt at a Solution


My mesh equations are:
-Vs + I1(30-12.5j)-I2(120j)=0
4Ix+I2(120j+20)-I1(120j)=0
Ix = (I1-I2)

Are these correct? When I solve I get a different result than when I do nodal analysis.
 
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Your first mesh equation is missing a term for the potential drop over the inductor due to mesh current ##I1##.
 
gneill said:
Your first mesh equation is missing a term for the potential drop over the inductor due to mesh current ##I1##.
-Vs + I1(30-12.5j+120j)-I2(120j)=0

i1 = (1.93736+0.385512i)
i2 = (1.83193+0.694348i)

ix = (1.93736+0.385512i)-(1.83193+0.694348i)
V(120j) = ix*120j = 37.06+j12.65 V
The solution (using nodal analysis) says V(120j) = 2.95+j1.126
 

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