How to Express a Complex Number in the Form of I-Tan(kA)?

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To express the complex number z = CosA + iSinA in the form I-Tan(kA), the discussion revolves around simplifying the expression 2/(1+z). The challenge lies in manipulating the expression using trigonometric identities and de Moivre's theorem. One suggested method involves multiplying by the conjugate (1-z) to simplify the denominator. The goal is to rewrite the result in the desired format, which may require further simplification. Ultimately, the solution hinges on correctly applying these mathematical principles.
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Someone solve this please!

If z= CosA+iSinA, express 2/1+z in the form I-Tan(kA).
 
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Well,what is that number (2/(1+z)) equal to?

And what do you mean by "I-Tan(kA)"...?

Daniel.
 
where k is a constant and A is the angle from above, it says to express the answer in that form- z is a complex number in polar form.
I tried multiplying the 2/(1+z) by the conjugate (1-z) on the top and bottom but I can't get it into the form 1-Tan(kA).
I think this involves trignometric identities and de Moivre's theorem.
 
you write z as (cosA + i SinA) and multilply the denominator by (1+ CosA --iSinA)...Simplify it...
Answer will come
 
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