How to Fill a 7.2m Pool in 2 Hours

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To fill a 7.2 m diameter pool to a depth of 1.5 m using a 5/8-inch diameter hose with water flowing at 0.28 m/s, the volume of the pool is calculated to be 61.1 m³. The flow rate through the hose, after correcting for diameter, is approximately 8.9 x 10^-3 m³/s. With these figures, it would take about 6865.2 seconds, or roughly 2 hours, to fill the pool. However, a conversion error regarding the hose diameter was noted, leading to a recalculation that suggested an unrealistic fill time of 13 days. The discussion confirms that while the method is sound, accurate measurements are crucial for realistic estimates.
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A 5/8-inch diameter hose is used to fill a round pool 7.2 m in diameter. How long will it take to fill it to a depth of 1.5 m if water leaves the hose at 0.28 m/s?

V_{pool} = \pi(3.6)^2 \cdot 1.5 = 61.1 \mbox{m}

5/8 in = 0.127m, r_{hose} = 0.063.5

V/s = \pi(0.063.5)^2 \cdot 0.28 = 8.9 \cdot 10^{-3}

\frac{61.1}{8.9 \cdot 10^{-3}} = 6865.2 s = 2 h

Look ok?
 
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no.
0.127m = 5 inches, not 5/8 of an inch.
 
tony873004 said:
no.
0.127m = 5 inches, not 5/8 of an inch.

:smile: that would make sense. I guess my converter doesn't like fractions.

Besides that, is the method ok?
 
Hmm... I get 13 days if I fix the conversion (d = 0.0159m.) This seems like a bit much.
 
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cscott said:
Hmm... I get 13 days if I fix the conversion (r = 0.0159m.) This seems like a bit much.
The method sounds right to me.
This is a huge pool to be filled with a tiny hose! several day si snot surprising to me.
 
The hose is 5/8 inch diameter, not radius. But yes, the method works withthe correct numbers.
 
Alright, thanks!
 
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