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## Homework Statement

A mass of 120g rolls down a frictionless hill reaching a speed of 4.2 m/s and collides with another mass 3.00g attached to a spring of constant 30 N/m. The two masses stick together and enter into periodic motion. What is the equation for the motion?

## Homework Equations

m1v1+m2v2=mtV

x(t)=Acos(wt+phi)

w=k/m^1/2

Vmax=wA

## The Attempt at a Solution

I found Vfinal=1.2 m/s

Also found w=8.45 rad by w=k/m^1/2

I thought A would be 0.142 but in the answer A=0.266

the answer is: x(t)=0.266sin(8.44t)