How to Find B_n in a Fourier Series Problem on the Interval -L < x < L?

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To find B_n in the Fourier series expansion of the function phi(x)=1 for 0<x<pi, an even extension of the function is necessary to cover the interval from -pi to pi. For part b, extending the function to the interval -2pi to 2pi requires an odd extension at x=pi, which results in the function being -1 from pi to 2pi. The convergence of the series occurs at specific points within this interval, and determining these points involves analyzing the behavior of the series. Additionally, Parseval's equality can be applied to calculate the sum of the series 1 + 1/(3^2) + 1/(5^2) + 1/(7^2) + ..., linking it to the Fourier coefficients. Understanding these extensions and convergence criteria is crucial for solving the problem effectively.
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Hi, I need help on the following problem on Fourier series:

Let phi(x)=1 for 0<x<pi. Expand
1 = \sum\limits_{n = 0}^\infty B_n cos[(n+ \frac{1}{2})x]
a) Find B_n.
b) Let -2pi < x < 2pi. For which such x does this series converge? For each such x, what is the sum of the series?
c) Apply Parseval's equality to this series. Use it to calculate the sum
1 + 1/(3^2) + 1/(5^2) + 1/(7^2) + ...

I know the formula for B_n for a function's Fourier series on the interval -L < x < L, so in this question I need to do some kind of odd or even extension for parts a and b, but I don't know how. Please help. Thanks.
 
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Ok, actually for part a, I'm pretty sure I should do an even extension of the function at x=0 so that it runs from -pi to pi. And I can then determine the B_n's.

But for part b, it looks like I need to somehow extend to -2pi to 2pi. I looked in books, and does an odd extension at x=pi so that function is -1 from pi to 2i. But I don't understand why. And how would I find the x's for the series to converge?
 
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