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How to find radians

  1. Jan 19, 2009 #1
    I do not need you to give me an answer just a formula

    I have some problems to work and I cannot find anything through searching, I can make up a problem, but for example

    find sin3x if sinx=1/3 and 0 < or equal to sin greater than or equal to pie/2

    How would I find x? I now how to plug in a radian into my calculator to get the answer the opposite way but not this way.
     
  2. jcsd
  3. Jan 19, 2009 #2

    Mark44

    Staff: Mentor

    Put your calculator down. You don't need it for any of this. If you want the exact answer, you don't need it at all.

    You need the formula for the sine of the sum of two angles.
    sin(3x) = sin(2x + x) = ??

    You'll get an expression involving sin(2x), sin(x), cos(2x), and cos(x).

    Convert the sin(2x) and cos(2x) factors by using the double-angle formulas for sin and cos.

    After you have done all that, you should have an expression that involves only sinx and cosx. You're given that sinx = 1/3, and I believe you are given than 0 < x < pi/2 (not pie/2). If you know that sinx = 1/3 and that x is in the first quadrant, what must cosx be?
     
  4. Jan 20, 2009 #3
    How would I find it if the roles were reversed, lets say

    cos2theta = 1/3 and find costheta?

    I understand the double angle formula, but I do not understand howto apply it in this case.
     
  5. Jan 20, 2009 #4

    Mark44

    Staff: Mentor

    The double-angle formula doesn't apply here. Instead, you need to use the inverse of the cosine function.

    Given that cos([itex]2\theta[/itex]) = 1/3, then [itex]2\theta[/itex] = cos-1(1/3), so [itex]\theta[/itex] = 1/2 cos-1(1/3).

    Hopefully there are some restrictions on [itex]\theta[/itex], but once you know it, you can determine cos([itex]\theta[/itex]).
     
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