How to find speed with just height given?

In summary, the conversation discusses designing a roller coaster with a starting height of 26.0 m and no friction. The speed at the bottom of the valley is determined to be 22.5 m/s using the equation v^2=2gh. For part b, the equation M=rv^2/g is used, but the radius ends up being too small. The meaning of 8g is not specified.
  • #1
Sneakatone
318
0
you are to design a roller coaster in which cars start from rest at a height h=26.0 m , roll down into a valley and then up a mountain. neglect friction.

a) what is the speed of the cars at the bottom of the valley?

B)if the passangers are to feel 8g at the bottom of the valley, what must be the radius R of the arc of the circle that fits the bottom of the valley?

c)the top of the next mountain is an arc of the circle of the same radius R. if the passengers are to feel 0g at the top what must be its height h?

there is a given picture, I do not know where to start.
 

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  • #2
You're told there's no friction. What equation does that allow you to write down wrt energy?
When you've worked out the speed at the bottom, do you have an equation relating speed, radius of curvature and acceleration?
 
  • #3
v^2=2gh
sqrt(2*9.81*26)=22.5 m/s

for part b I tried to use M=rv^2/g but the radius ended to be too small.
 
Last edited:
  • #4
Sneakatone said:
for part b I tried to use M=rv^2/g but the radius ended to be too small.
That's a strange looking equation. What's M? It seems to have dimensions of area.
 
  • #5
Sneakatone said:
v^2=2gh
sqrt(2*9.81*26)=22.5 m/s
Correct.

Sneakatone said:
for part b I tried to use M=rv^2/g but the radius ended to be too small.
What 8g means?
 

1. How do you find speed with just height given?

To find speed with just height given, you can use the equation for gravitational potential energy: PE = mgh. Then, you can use the conservation of energy principle to equate the potential energy at the initial height (PEi) to the kinetic energy at the final height (KEf) and solve for speed. This can be represented as KEf = 1/2mv^2 = PEi = mgh. Therefore, the final equation for finding speed with just height given is v = √(2gh).

2. Can you use this method to find speed for any object?

Yes, this method can be used to find speed for any object, as long as the initial height and final height are known. This is because the equation for gravitational potential energy and the conservation of energy principle apply to all objects.

3. Does this method only work for objects in free fall?

No, this method works for any object that is moving due to gravity, not just objects in free fall. This includes objects on an incline, projectiles, or even objects falling with air resistance. As long as the object is moving due to gravity, this method can be used to find its speed.

4. What units should be used for height and speed in this equation?

The units for height should be in meters (m), and the units for speed will be in meters per second (m/s). This is because the standard unit for height and distance is meters, and the standard unit for speed is meters per second.

5. Are there any limitations to using this method?

While this method is generally accurate, it does have some limitations. One limitation is that it assumes no external forces acting on the object besides gravity. It also does not take into account air resistance, which can affect the actual speed of the object. Additionally, this method only gives the speed at the final height and does not account for any changes in speed during the object's motion.

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