How to find speed with just height given?

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The discussion focuses on designing a roller coaster starting from a height of 26.0 m, with calculations for speed at the valley's bottom and the radius required for specific g-forces. The speed at the bottom is calculated using the equation v^2 = 2gh, resulting in 22.5 m/s. For the radius at the bottom of the valley to achieve 8g, the correct relationship between mass, radius, and acceleration is questioned, as the initial attempts yielded an impractically small radius. Clarification is sought on the meaning of "8g" in this context. The conversation emphasizes the importance of energy conservation and correct application of physics principles in roller coaster design.
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you are to design a roller coaster in which cars start from rest at a height h=26.0 m , roll down into a valley and then up a mountain. neglect friction.

a) what is the speed of the cars at the bottom of the valley?

B)if the passangers are to feel 8g at the bottom of the valley, what must be the radius R of the arc of the circle that fits the bottom of the valley?

c)the top of the next mountain is an arc of the circle of the same radius R. if the passengers are to feel 0g at the top what must be its height h?

there is a given picture, I do not know where to start.
 

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You're told there's no friction. What equation does that allow you to write down wrt energy?
When you've worked out the speed at the bottom, do you have an equation relating speed, radius of curvature and acceleration?
 
v^2=2gh
sqrt(2*9.81*26)=22.5 m/s

for part b I tried to use M=rv^2/g but the radius ended to be too small.
 
Last edited:
Sneakatone said:
for part b I tried to use M=rv^2/g but the radius ended to be too small.
That's a strange looking equation. What's M? It seems to have dimensions of area.
 
Sneakatone said:
v^2=2gh
sqrt(2*9.81*26)=22.5 m/s
Correct.

Sneakatone said:
for part b I tried to use M=rv^2/g but the radius ended to be too small.
What 8g means?
 
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