Chemistry How to find the molecular formula out of the molar mass?

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To find the molecular formula from a given molar mass, first determine the mass of the empirical formula, which in this case is CH, totaling 13 g. Divide the molar mass of the compound (78 g) by the empirical formula mass (13 g) to find the number of empirical units, yielding six. Multiply the subscripts in the empirical formula by this number to derive the molecular formula, resulting in C6H6, which is benzene. For the second question regarding potassium chloride, calculate its molar mass (74.6 g) and divide the given mass (35 g) by this value to find the number of moles, which is approximately 0.47 moles. Understanding these calculations is essential for determining molecular formulas and moles in chemistry.
jessicah211
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Here is the problem. I have a series of questions that I don't know how to do. They are all basically the same so I will just give an example of one and if I could get a point the right direction that would be great!

The molar mass of an important industrial solvent is 78.0 g and its empirical formula is CH. What is its molecular formula?

Anther slightly related question that might be answered as part of the first question is

How many moles are in 35 g of potassium chloride?
 
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What is molar mass of the hypothetic CH group? How many such groups are needed for the molecule to have molar mass of 78?
 
As Borek said,

(CxHy)n = 78.0 (You are given 1 x and 1 y)

1) Find the mass of the hypothetical group
here : x (mass of carbon = 12) + y (mass of hydrogen = 1) = 13

2) Find how many possible hypothetical groups you can have for 78.0 g
here : n = 78.0 / 13.0 = 6,

3) Just multiply replace x,y and n and you will get the actual formula
here : (C1H1)6 = C6H6

... and you found Benzene :)

The second part is as simple. Just use a periodic table to find the mass of K and Cl, thus finding the mass of 1 mole of KCl, then just divide the mass given in the question:

1 mole = (35.5 + 39.1) 74.6 g
35 g = ( 35 / 74.6 ) 0.47 moles
 
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