How to handle leftover terms in integration after substitution?

[Triggy]

How do you integrate $$\int secx^{3}tanxdx$$

I'm substituting $$u = tanx$$ so $$du = sec^2xdx$$Now the problem is when I made sec^3x into sec^2xsecx then I had a secx left over after my substitution. What do I do with this?

PS: Sorry I'm new at latex and I don't know how to get rid of that {

 

[Kurdt]

Try sec(x) = u and substituting. When you differentiate this it may become clearer.

 

[Triggy]

Aahh! Thanks tending to infinity man. I got it.

$$\{1/3sec^3x} [\tex]$$

 

[Triggy]

Is there like a post on how to use latex?

 

[Kurdt]

Is there like a post on how to use latex?

If you click on latex images it shows you the code and there is a link below the code to a short PDF with a few tips and small tutorial.

https://www.physicsforums.com/misc/howtolatex.pdf

 

[George Jones]

PS: Sorry I'm new at latex and I don't know how to get rid of that {

Delete the \{ and the }.

 

[Triggy]

Awsome. Thanks Kurdt and GJ