How to Integrate by Parts Twice for e^3x cos(x)?

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To solve the integral ∫ e^(3x) cos(x) dx, integration by parts is required twice. The user initially struggled with the problem but eventually derived the solution as (e^(3x) sin(x) + 3e^(3x) cos(x)) / 10. This result was confirmed by another participant in the discussion. The conversation highlights the importance of understanding integration techniques in preparation for midterms. Mastery of such problems is essential for success in calculus.
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I am studying for a midterm, was browsing over an old midterm and found this question


<br /> \int e^{3x} \cos{(x)}\; dx <br />

Can't figure it out, help would be appreciated
 
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Integrate by parts twice. Post back if you get stuck.
 
erm didn't think we'd gotten that far, assignment on that section isn't due until monday. No wonder I couldn't find it hehe.

O well I have 2 hrs to learn it I'm good! :)
 
hmm I ended up with

<br /> \int e^{3x} \cos{(x)}\; dx = \frac{e^{3x}\sin{(x)} + 3e^{3x} \cos{(x})} {10}<br />

that sound about right?
 
Looks good to me.
 
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