MHB How to know if plane is perpendicular to another plane?

Click For Summary
SUMMARY

This discussion focuses on determining vector equations for planes and lines that are perpendicular to given axes and lines. A plane perpendicular to the z-axis can be expressed as 0x + 0y + 1z = C, where C is a constant. For the line defined by the equation 2x + 3y = 6, the perpendicular line has a slope of 3/2 and can be represented as y = (3/2)x + 2 or equivalently as 2y - 3x = 2. The key to solving these problems lies in identifying normal vectors and comparing slopes.

PREREQUISITES
  • Understanding of vector equations in three-dimensional space
  • Knowledge of slopes and intercepts in two-dimensional linear equations
  • Familiarity with the concept of normal vectors
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the concept of normal vectors in vector calculus
  • Learn how to derive equations of lines and planes from given geometric conditions
  • Explore the relationship between slopes of perpendicular lines in coordinate geometry
  • Practice solving vector equations for various orientations and dimensions
USEFUL FOR

Students of mathematics, geometry enthusiasts, and anyone involved in physics or engineering requiring a solid understanding of vector equations and their applications in three-dimensional space.

nicole1
Messages
1
Reaction score
0
The question that I'm trying to answer states "Make a vector equation of a plane that is perpendicular to the z axis." How do i ensure its perpendicular? How do i start this equation?

Another question similar to this that i am also struggling states "What is the vector equation of a 2D line that is perpendicular to this line: 2x + 3y = 6 though the lines y intercept?"

Any help for both of these questions would be greatly appreciated!
 
Physics news on Phys.org
nicole said:
The question that I'm trying to answer states "Make a vector equation of a plane that is perpendicular to the z axis." How do i ensure its perpendicular? How do i start this equation?

Another question similar to this that i am also struggling states "What is the vector equation of a 2D line that is perpendicular to this line: 2x + 3y = 6 though the lines y intercept?"

Any help for both of these questions would be greatly appreciated!

Find a NORMAL VECTOR to the Planes. If they are orthogonal, you're done.

Rather the same deal for the lines. Compare the slopes.
 
Any plane can be written in the form Ax+ By+ Cz= D for constants A, B, C, and D. And then <A, B, C> is a vector normal (perpendicular) to that plane.

The z-axis has "unit direction vector" <0, 0, 1>. A plane perpendicular to it must have that as "normal vector" and so the equation of the plane can be taken as 0x+ 0y+ 1z= z= C for some constant C.

The line 2x+ 3y= 6 has y-intercept (0, 2) (the y-intercept of a line is the point where it crosses the y-axis so x= 0). Further, if we were to "solve" that equation for y, 3y= 6- 2x, so y= 2- (2/3)x. That shows, again, that the y-intercept is 2 and that the slope is -2/3. A line perpendicular to the given line must have slope 3/2. Any (non-vertical) line can be written in the form y= mx+ b where m is the slope and b is the y-intercept. A line with slope 3/2 and y-intercept 2 is y= (3/2)x+ 2. If you don't like fractions, multiply by 2 to get 2y= 3x+ 2 which can be written in the same form as the line was originally given as 2y- 3x= 2.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 36 ·
2
Replies
36
Views
6K
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K