Preparing NaOH Reagent: Diluting 0.32M Solution with Water

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To prepare a 0.32M NaOH solution, dilute 1 part of the NaOH solution with 4 parts of distilled water. This means mixing 1 mL of the NaOH solution with 4 mL of water. The dilution process is correct as it reduces the concentration of the original solution. However, the discussion raises concerns about the completeness of the problem, as it only provides one concentration without specifying a starting concentration for the dilution. Clarification on whether a more concentrated solution exists is necessary for accurate preparation.
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Homework Statement


There is a reagent given . NaOH with concentration of 0,32 mol/ L
HOw to prepare it ?
it says dilute 1 part by volume of solution Naoh with 4 parts by volume of redist.water ??
(Neglect the total volume that you need , it's not important ) just the process to make it

Homework Equations


cxv=cxv

The Attempt at a Solution


Is it correct if i say 1 mL of naoh solution and 4 ml of water ?
 
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Problem doesn't look complete to me. You say you have a reagent and you are asked to prepare it. You either have it, or you have to prepare it.

And dilution is used to prepare a solution with a lower concentration from a more concentrated solution. You listed only one concentration, so there is not enough information to calculate any dilutions.
 
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