How to Prove a Multivariable Function Converges to a Specific Value?

[PsychonautQQ]

Homework Statement

How do I prove the function ((2^x)-1)sin(y))/(xy) converges to ln(2) in the case of x=0 and y=0..?

Homework Equations

The Attempt at a Solution

Yeah I'm trying to figure out where to start honestly... I know I'm not suppose to post unless I have a real attempt at the solution.. I could BS something but anyone want to point me in the right direction? Squeeze Theorem? Is there some key property I should be aware of?

 

[LCKurtz]

Homework Statement

How do I prove the function ((2^x)-1)sin(y))/(xy) converges to ln(2) in the case of x=0 and y=0..?

Homework Equations

The Attempt at a Solution

Yeah I'm trying to figure out where to start honestly... I know I'm not suppose to post unless I have a real attempt at the solution.. I could BS something but anyone want to point me in the right direction? Squeeze Theorem? Is there some key property I should be aware of?

Why do you think the answer is $\ln 2$? Try some special limits to get a feel for it. What if $y\rightarrow 0$ before $x$, for example.

 

[PsychonautQQ]

the answer is ln(2), the question says that, we just have to PROVE it is.

 

[dirk_mec1]

Yes, the answer is indeed ln(2) I used mclaurin series to prove it.

 

[pasmith]

Homework Statement

How do I prove the function ((2^x)-1)sin(y))/(xy) converges to ln(2) in the case of x=0 and y=0..?

Homework Equations

The Attempt at a Solution

Yeah I'm trying to figure out where to start honestly... I know I'm not suppose to post unless I have a real attempt at the solution.. I could BS something but anyone want to point me in the right direction? Squeeze Theorem? Is there some key property I should be aware of?

Your function is a function of x only times a function of y only:
<br /> \frac{(2^x - 1)\sin y}{xy} = \frac{2^x - 1}{x} \frac{\sin y}{y}<br />

One can show that if \lim_{x \to 0} f(x) and \lim_{y \to 0} g(y) exist then
<br /> \lim_{(x,y) \to 0} f(x)g(y) = \left(\lim_{x \to 0} f(x) \right)\left( \lim_{y \to 0} g(y) \right)<br />

Also remember that
<br /> \lim_{x \to 0} \frac{f(x) - f(0)}x = f&#039;(0)<br />
assuming the limit exists.