kuahji
- 390
- 2
\sum (2^(2n)-(-7)^n)/(11^n)
The book has that expression equal to
\sum (4/11)^n - \sum (-7/11)^n
I'm not seeing how the first part changes to (4/11)^n. Wouldn't it be (2^2+2^n) & not 4^n? Or is there something else I'm missing?
The book has that expression equal to
\sum (4/11)^n - \sum (-7/11)^n
I'm not seeing how the first part changes to (4/11)^n. Wouldn't it be (2^2+2^n) & not 4^n? Or is there something else I'm missing?