How to Simplify the Hamiltonian for a Homogeneous System in Scaled Coordinates?

Click For Summary
The discussion focuses on simplifying the Hamiltonian for a homogeneous system in scaled coordinates, specifically addressing the conversion of the integral involving density n. The initial terms can be expressed as + , but challenges arise with the term -½* ∫ d³r d³r' (n²/|r-r'|). The scaled coordinates are defined as \tilde{r} = a_0/r_s, leading to the expression -\frac{3}{4\pi} ∫ d³\tilde{r} (1/\tilde{r}). The main issue is reducing the double integral d³r d³r' to a single integral d³\tilde{r}, with hints sought for resolving this complexity.
greisen
Messages
75
Reaction score
0
I have to show that the hamiltonian for a homogeneous system can be simplified in scaled coordinates.
The first two terms I can convert to scaled coordinates <T>+<V> whereas I have some trouble for the last term

-½*\int d³r d³r&#039; \frac{n²}{|r-r&#039;|}

where n is the density. The scaled coordinates can be expressed as \tilde{r}=\frac{a_0}{r_s} - r_s is a average distance between electrons and the expression can be written as

-\frac{3}{4\pi} \int d³\tilde{r} \frac{1}{\tilde{r}}

I have some troubles getting the last part - how can the two d³r d³r' be reduced to d³\tilde{r} - any hints or advise appreciated
thanks in advance
 
Last edited by a moderator:
Physics news on Phys.org
I can see that some of the exponents have vanished so the integral which gives me problems is

- \int dr^{3} dr'^{3} \frac{n^{2}}{|r-r'|}

which in scaled coordinates can be written as

- \frac{3}{4*pi}\int d\tilde{r}^{3} \frac{1}{\tilde{r}}
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 46 ·
2
Replies
46
Views
5K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K