The discussion focuses on solving a material balance problem involving two liquids, A and B, with specific solid concentrations. Liquid A contains 5.00% solids and liquid B contains 11.0% solids. After adding 18.5 kg of bone-dry solids to a mixture totaling 2150 kg with 8.25% solids, the original amounts of liquids A and B were determined to be 1260 kg and 872 kg, respectively. The participants also explored the equations necessary for solving similar problems, including mass balances for solids and water.
PREREQUISITESChemical engineers, process engineers, and students studying material balances in chemical processes will benefit from this discussion.
one example related toBystander said:How many equations in how many unknowns?
initial amount of A n B in the total mixture. How much kg of A and B was added in the mixtureChestermiller said:In terms of A and B, what is the total mass of the final mixture?
In terms of A and B, what is the mass of solids in the final mixture?
Chet
Answers for this question is, A = 1260 kg, B = 872 kgChestermiller said:In terms of A and B, what is the total mass of the final mixture?
In terms of A and B, what is the mass of solids in the final mixture?
Chet
I have no idea what you are saying here. Can you please answer the questions I asked (in the form of equations).nahian taskin said:initial amount of A n B in the total mixture. How much kg of A and B was added in the mixture
No equations are given. From this, We have to make our own equation to get the solution.Chestermiller said:I have no idea what you are saying here. Can you please answer the questions I asked (in the form of equations).
Chet
how many equations it can be here, that's the confusion because i don't know wether its a batch process or rate process.nahian taskin said:No equations are given. From this, We have to make our own equation to get the solution.
I have tried with this equation:
For solid : 0.05A+ 0.11B = 18.5+ 2150(0.08125)
For Water: 0.95A+ 0.89B = 2150(0.9175)
solve the equations.
but i wrong answer,which means something is wrong in my equation
Batch process : total input = total output.nahian taskin said:how many equations it can be here, that's the confusion because i don't know wether its a batch process or rate process.
This is what I was looking for. Your formulation is very close to being correct. There are just a couple of minor errors.nahian taskin said:No equations are given. From this, We have to make our own equation to get the solution.
I have tried with this equation:
For solid : 0.05A+ 0.11B = 18.5+ 2150(0.08125)
For Water: 0.95A+ 0.89B = 2150(0.9175)
solve the equations.
but i wrong answer,which means something is wrong in my equation
if 8.25% is solid then (100-8.25)% is water which is 91.75%Chestermiller said:This is what I was looking for. Your formulation is very close to being correct. There are just a couple of minor errors.
1. In the solid equation, are you sure that 18.5 belongs on the right hand side of the equation?
2. In the water equation, recheck that 0.9175. There's an arithmetic error.
Chet
in the first equation i made a mistake it is 2150(0.0825) not 0.08125nahian taskin said:if 8.25% is solid then (100-8.25)% is water which is 91.75%
and i tried by giving 18.5 on the left hand side, but answer didnt came. It was more far than the actual answer.
nahian taskin said:in the first equation i made a mistake it is 2150(0.0825) not 0.08125
No, i didnt. I am now trying with by corrcting that value in the equationChestermiller said:I know. I just noticed that. Do you get the right answer now with the 18.5 on the left?
Chet
Didnt came again :( with this value .nahian taskin said:No, i didnt. I am now trying with by corrcting that value in the equation
Ohk, thank you :)Chestermiller said:Here are the equations I solved, and I got the correct answer:
For solid : 0.05A+ 0.11B + 18.5 = 2150(0.0825)
For Water: 0.95A+ 0.89B = 2150(0.9175)
If you didn't get the correct answer using these equations, then you need to check your algebra.
Chet