How to solve a Network Analysis

[baki]

1. The flow of traffic (in vehicles per hour) through a network of streets is shown below. The diagram shows :

200 and x2 is entering junction 1 and x1 is leaving the junction.
Junction 2, 100 and x1 is entering the junction and x3 is leaving the junction.
Junction 3, 200 and x4 is leaving the junction and x3 is entering the junction.
Junction 4, 100 and x2 is leaving the junction and x4 is entering the junction.




2. i.) Solve this system for xi, i = 1, 2, 3, 4.
ii.) Find the traffic flow when x2 = 50
iii.) If all directions are reversed, how would the solutions change?
iv.) Introduce at least on bypass/junction to the design and solve the new system.



3. i.) When it says solve for xi, meaning we have to come up with equations that can solve for x1, x2, x3 and x4? if that's the case then I have done that and my answer came to x1 +100 = x3, x3 = x4 + 200, x4 = 100 + x2, x2 + 20 = x1.

ii.) For this questions, from the equations i got from (i), i substitute 50 in place of x2, and then found x1, x3, x4.

iii.) the answer remains the same, because the everything is the same.

iv.) What exactly does does this question mean

 

[Ray Vickson]

1. The flow of traffic (in vehicles per hour) through a network of streets is shown below. The diagram shows :

200 and x2 is entering junction 1 and x1 is leaving the junction.
Junction 2, 100 and x1 is entering the junction and x3 is leaving the junction.
Junction 3, 200 and x4 is leaving the junction and x3 is entering the junction.
Junction 4, 100 and x2 is leaving the junction and x4 is entering the junction.




2. i.) Solve this system for xi, i = 1, 2, 3, 4.
ii.) Find the traffic flow when x2 = 50
iii.) If all directions are reversed, how would the solutions change?
iv.) Introduce at least on bypass/junction to the design and solve the new system.



3. i.) When it says solve for xi, meaning we have to come up with equations that can solve for x1, x2, x3 and x4? if that's the case then I have done that and my answer came to x1 +100 = x3, x3 = x4 + 200, x4 = 100 + x2, x2 + 20 = x1.

ii.) For this questions, from the equations i got from (i), i substitute 50 in place of x2, and then found x1, x3, x4.

iii.) the answer remains the same, because the everything is the same.

iv.) What exactly does does this question mean

Where is the diagram?

RGV