How to Solve Equations with Unknown Variables Using Trigonometric Identities

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Homework Statement


I have to solve the following equation:
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Homework Equations

The Attempt at a Solution


I know that since the right side is 1 and on the left side i have i (imaginary number) it means that i could rewrite right side as cos0 + isin0 since it's the same, but what can i do with left side, it obviously can't stay like this because of the product, i have to get rid of it, i just don't have an idea.
 
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What do you get when you replace the factors in the product using Euler's formula?
 
Samy_A said:
What do you get when you replace the factors in the product using Euler's formula?

As far as i know, we have Пekx (П is from 1 to n) which is equal to:

ex*e2x*...*enx or

e(1+2+...+n)x. Now, i am not 100% sure, but i believe is should represent 1+2+...+n as n(n+1)/2 and go back to the trigonometric form of number, and then simply find x since i know exact value of angle for the right side. Am i correct?
 
cdummie said:
As far as i know, we have Пekx (П is from 1 to n) which is equal to:

ex*e2x*...*enx or

e(1+2+...+n)x. Now, i am not 100% sure, but i believe is should represent 1+2+...+n as n(n+1)/2 and go back to the trigonometric form of number, and then simply find x since i know exact value of angle for the right side. Am i correct?
You forgot the ##i## in your exponent, as Euler's formula is ##cos(y)+isin(y)=e^{iy}##.
You are correct about ##\sum_{k=1}^n k =n(n+1)/2##.
As the product is equal to ##1##, you can now indeed solve for x by applying Euler's formula again: the cosine of your exponent (not including the ##i##) must be ##1##.
 
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How many solutions do you need? Just one, all of them for a fixed n, or all of them for any n?
##e^{iy} = 1 ## is true for an infinite number of periodic terms.
For a large w, ##e^{iwy} ## will have a much shorter period. Your w might get quite large as n grows.
 
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