How to tell that 1/(z+2i) is not analytic?

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The expression 1/(z+2i) is not analytic within the circle |z-2|=4 because it has a singularity at the point z=-2i, where the function is undefined. This singularity indicates that the function becomes infinite at that point, confirming it is not analytic there. To determine if a function is analytic, one can examine properties such as continuity and the behavior of limits from both sides. The discussion emphasizes the importance of identifying singularities and understanding the conditions under which a function is considered analytic. Thus, the presence of a singularity at z=-2i is the key factor in establishing that the function is not analytic in the specified region.
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hi as shown above, i have come across this expression. But i am not sure how to tell if it is not analytic in the circle |z-2|=4, clockwise.
expression: 1/(z+2i)

On top of that, can anyone give me a general idea of how to see if the expression is analytic or not analytic without using the cauchy's equation.

pls help. thx.
 
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Well, that circle contains the point -2i at which f(x) does not even exist.
 
but how do u tell that f(x) does not exist there?

does it mean the function will be come infinite when z=-2i and thus telling us it is not analytic at that point?
 
Last edited:
nutcase21 said:
but how do u tell that f(x) does not exist there?

does it mean the function will be come infinite when z=-2i and thus telling us it is not analytic at that point?

Consider the properties of divergence and also other analytic properties like limits: the limit must be the same from both sides and continuity must hold (among the other properties of analytic functions).
 
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