How to test cutoff frequency of IR filter on camera?

AI Thread Summary
To test the cutoff frequency of an IR filter on a camera, remove the filter and take a spectrum using a broad-spectrum light source, then reinsert the filter and take another spectrum to compare. This method will reveal the wavelengths that the filter attenuates or blocks completely. Essential equipment includes a well-calibrated light source, a spectrometer, and possibly optics for older spectrometers. A monochromator can also be used to illuminate the sensor and help determine the cutoff wavelength by comparing output intensities. This experiment can be conducted without needing advanced IR or UV equipment, focusing on wavelengths between 400nm and 700nm.
pgpgpgpg
Messages
1
Reaction score
0
Modern cell phones seems to come with IR filters on their cameras. I want to do an experiment to figure out what wavelengths these filters allow to pass and which they block. How would I go about doing this?
Also, what sort of equipment would I need? I am a university student so I have access to a nicely supplied physics lab. Thanks.
 
Physics news on Phys.org
Remove the filter; using a broad-spectrum source (e.g., a tungsten lamp) take a spectrum.
Now insert the filter and take another spectrum.

This will show you the attenuation for all wavelengths, and those which are blocked completely.

Your lab should have a well-calibrated light source and a spectrometer. If the equipment is modern it will be fiber coupled; if it is older there will be gratings inside, and you will have to use some optics to collimate the light into the spectrometer slit.
 
Alternatively, use the output of a monochromator to illuminate the sensor, compare the monochromator output intensity with the image intensity to (approximately) determine the cutoff wavelength.

You shouldn't have to go much beyond 700nm- no fancy IR equipment is needed. Same on the UV side- you should not have to go much below 400nm.
 
Andy Resnick said:
Alternatively, use the output of a monochromator to illuminate the sensor, compare the monochromator output intensity with the image intensity to (approximately) determine the cutoff wavelength.

We pop the filters off from cheap web cams so that they can pick up near infrared (700-850 nm or so) in our laser lab. But if you plan to put it back, you may prefer the non-destructive route.
 
This is from Griffiths' Electrodynamics, 3rd edition, page 352. I am trying to calculate the divergence of the Maxwell stress tensor. The tensor is given as ##T_{ij} =\epsilon_0 (E_iE_j-\frac 1 2 \delta_{ij} E^2)+\frac 1 {\mu_0}(B_iB_j-\frac 1 2 \delta_{ij} B^2)##. To make things easier, I just want to focus on the part with the electrical field, i.e. I want to find the divergence of ##E_{ij}=E_iE_j-\frac 1 2 \delta_{ij}E^2##. In matrix form, this tensor should look like this...
Thread 'Applying the Gauss (1835) formula for force between 2 parallel DC currents'
Please can anyone either:- (1) point me to a derivation of the perpendicular force (Fy) between two very long parallel wires carrying steady currents utilising the formula of Gauss for the force F along the line r between 2 charges? Or alternatively (2) point out where I have gone wrong in my method? I am having problems with calculating the direction and magnitude of the force as expected from modern (Biot-Savart-Maxwell-Lorentz) formula. Here is my method and results so far:- This...
Back
Top