How to work with the double sum?

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Homework Statement



What is \sum_{n=0}^{\infty} (-1)^n\sum_{k=0}^{n} n!/(n-k)!* ln^{n-k}(2)?

Homework Equations





The Attempt at a Solution


How to work with the double sum?
 
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Could I combine the two sums into one? I am not sure how, but I have a feeling that is what I am supposed to do. Thanks.
 
seanhbailey said:

Homework Statement



What is \sum_{n=0}^{\infty} (-1)^n\sum_{k=0}^{n} n!/(n-k)!* ln^{n-k}(2)?

Homework Equations





The Attempt at a Solution


How to work with the double sum?

seanhbailey said:
Could I combine the two sums into one? I am not sure how, but I have a feeling that is what I am supposed to do.
I don't think you can, but I could be wrong.

I would start expanding it and see if that gets me anywhere. One thing that bothers me is that you will have numerous expressions with ln0(2). I don't know what that means, but maybe it's supposed to represent just plain 2.

If you start expanding the double sum, you get:
(+1)*( 2) ; n = 0
+ (-1)*(1!/1! * ln(2) + 1!/0! * 2) ; n = 1, k = 0, k = 1
+ (+1)*(2!/2! * ln2(2) + 2!/1! * ln(2) + 2!/0! * 2) ; n = 2, k = 0, 1, 2
and so on.
 
I am getting that the sum goes to infinity- is this right?
 
Looks that way to me. The limit of the nth term of the series isn't zero, so the series diverges.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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