How Would Gravity Work on a Planet-Sized Ring?

AI Thread Summary
Gravity on a planet-sized ring would depend on its rotation speed and structure. Walking on the outside of the ring is feasible if it rotates fast enough to create sufficient centrifugal force. The center of mass and gravity would be located at the center of the ring, influencing the gravitational pull experienced on its surface. Inside the ring, gravity would not be zero, as it is strongest near the surface, but walking there would feel similar to being in a centrifuge, pushing occupants outward. The discussion highlights the complexity of gravitational forces in such a unique structure, suggesting further exploration of concepts like "ringworld" for deeper understanding.
DaSi14
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Hello,

I was wondering what the effect of gravity in a planet sized ring would be. If any of you have played the Halo game series, the ring structure is what I have in mind.

-Would you be able to walk on the inside of the ring, and what forces will or will not permit you to?
-Would you be able to walk on the outside of the ring, and what forces will or will not permit you to?
-And can you explicitly identify where the center of mass and gravity are and how they are involved with the forces above?

My line of reasoning is that center of mass and gravity would be in the center of the ring, which would mean that you are able to walk on the outside of the ring, provided that it rotates fast enough.
However, I'm not sure what would happen if you were to try to walk on the inside of the ring. My intuitions compares it to a centrifuge, where if something was spinning fast enough, the contents on the inside would be pushed against the wall, but it conflicts with how I think about the scenario where I walk on the outside of the ring. I hope this makes sense.

Thanks!
 
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do a forum search. This topic was beat to death here recently. Probably searching for "ringworld" or "larry niven" will turn it up since they were mentioned incidentally in the thread.

EDIT: I see rcgldr beat me to it.
 
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