None of this is right. We have $$y_1+\frac{p_1}{\gamma}+\frac{v_1^2}{2g}=80\ ft$$From the information provided in the problem statement, what are ##y_2##, ##\frac{P_2}{\gamma}##, and ##\frac{v_2^2}{2g}##?fayan77 said:
Correctfayan77 said:
Who says?[/QUOTE]
For any reservoir, dh/dt is usually small.fayan77 said:
Energy loss in a long pipeline refers to the decrease in pressure and flow rate of a fluid as it travels through the pipeline. This is caused by various factors such as friction, changes in elevation, and bends in the pipeline.
Friction between the fluid and the walls of the pipeline causes energy to be converted into heat, resulting in a decrease in pressure and flow rate. This is known as frictional head loss and is dependent on the fluid velocity and the roughness of the pipeline walls.
Changes in elevation, such as an increase or decrease in the pipeline's height, can lead to energy loss in a long pipeline. When the fluid moves to a higher elevation, it gains potential energy and loses kinetic energy, resulting in a decrease in pressure and flow rate. The opposite occurs when the fluid moves to a lower elevation.
Bends in a pipeline cause the fluid to change direction, resulting in a loss of kinetic energy and an increase in pressure. The sharper the bend, the greater the energy loss. This is known as bend or curvature head loss.
There are several ways to reduce energy loss in a long pipeline, including using larger diameter pipes to decrease friction, minimizing changes in elevation, and using smoother pipeline materials to reduce friction. Additionally, installing straightening vanes or flow control devices at bends can help reduce energy loss. Regular maintenance and proper design of the pipeline can also help minimize energy loss.
