Hypothesis test (binomial) problem

  • Thread starter Thread starter coconut62
  • Start date Start date
  • Tags Tags
    Binomial Test
Click For Summary

Homework Help Overview

The problem involves a hypothesis test concerning a potentially biased die, specifically focusing on the occurrence of the number four when rolled multiple times. The subject area pertains to statistics, particularly binomial distributions and hypothesis testing.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the setup of the hypothesis test, including the null and alternative hypotheses. There is a focus on the calculation of probabilities related to the binomial distribution and the interpretation of results. Some participants question the validity of the conclusion drawn from the test.

Discussion Status

The discussion is ongoing, with participants expressing differing views on the correctness of the original poster's conclusion. Some participants agree with the original poster's assertion that the conclusion may be incorrect, indicating a productive exploration of the problem.

Contextual Notes

The original poster's approach includes specific calculations and a conclusion based on a significance level, but there is a lack of consensus on the interpretation of these results. The discussion reflects an examination of assumptions regarding the die's bias.

coconut62
Messages
161
Reaction score
1

Homework Statement



Hester suspected that a die was biased in favour of a four occurring. She decided to carry out a hypothesis test. When she threw the die 15 times, she obtained a four on 6 occasions. Carry out the test, at the 5% level, stating your conclusion clearly.

Homework Equations


None.


The Attempt at a Solution



Ho: p = 1/6
H1: p > 1/6

If Ho is true, then X~B (15, 1/6)
Reject Ho if P (X >= 6) < 5%

P (X >= 6) = 1 - P(X <=5)

= 1- (5/6)^15 - (15C1)(1/6)(5/6)^14 - (15C2)(1/6)^2 (5/6)^13 - (15C3)(1/6)^3 (5/6) ^12 -(15C4)(1/6)^4 (5/6)^11 -(15C5)(1/6)^5 (5/6)^10

=0.0274
=3% (1 s.f.)

Since P (X>=6) < 5%, reject Ho.

The die is biased in favour of 4.

(Answer: no evidence that shows die is biased)

Why am I wrong?
 
Physics news on Phys.org
In my view, you're right. The answer must be wrong.
 
PeroK said:
In my view, you're right. The answer must be wrong.

I agree.
 
Thanks.
 

Similar threads

Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
3K
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K