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jkh4
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I don't understand for integral ysin(xy)dx = -cos(xy) for a=1 b=2. I know sin's integral is cos, but I don't understand how to eliminated the y in the left equation so it become the right equation. Please help!
jkh4 said:I don't understand for integral ysin(xy)dx = -cos(xy) for a=1 b=2. I know sin's integral is cos, but I don't understand how to eliminated the y in the left equation so it become the right equation. Please help!
jkh4 said:what about this one?
how do you integrate x(y^2 - x^2)^(1/2)? my TA says the answer is (-1/3)((y^2 - x^2)^(3/2)) but i don't get where is the (-1/3) comes from...
jkh4 said:this is the process i got so far
(x^2/2)((y^2-x^2)^(3/2))/(3/2)(-1/x^2)
but one thing i don't understand, for the (-1/X^2), is this a proper intergral step?
Solving integrals can be challenging, but there are several methods that can help. You can use integration by parts, substitution, or partial fractions to solve the integral. It's also important to carefully consider the limits of integration and any known properties of the function.
The integral is a fundamental concept in calculus that represents the area under a curve. It has many applications in physics, engineering, and other sciences. It can also be used to find important quantities such as volume, work, and displacement.
Choosing the right method for solving an integral depends on the form of the function and any known properties. It's important to understand the different methods and their applications in order to make an informed decision. Practice and experience also play a role in developing this skill.
If you are unable to solve an integral, there are several resources available to help. You can consult with a tutor or professor, use online tools and calculators, or refer to textbooks and other reference materials. It's also important to review the fundamentals of calculus and practice solving simpler integrals before attempting more complex ones.
In some cases, it may be possible to solve an integral without using calculus. This can be done by using geometric techniques, such as finding the area of a shape, or by using properties of the function to simplify the integral. However, calculus is often the most efficient and accurate method for solving integrals.