I have a few questions, this one is special relativity.

AI Thread Summary
The discussion revolves around a thought experiment in special relativity involving twin astronauts, one of whom travels at 0.98c and returns after 20 Earth years. Participants clarify the calculation of the Lorentz factor (gamma) using the formula 1/sqrt(1 - v^2/c^2), leading to a gamma value of approximately 5.03. This factor indicates that while 20 years pass for the Earth twin, the traveling twin ages only about 5.03 years, resulting in an age of approximately 30 years upon return. The confusion primarily stems from how to apply the gamma factor to determine the traveling twin's age correctly. Ultimately, the astronaut twin ages significantly less than his Earth-bound counterpart due to the effects of time dilation.
chevycamaro1987
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1. On his 25th birthday, the astronaut twin leaves on a long space journey at an average speed of v/c= 0.98. He returns after 20 earth-years have elapsed, to celebrate his earth-twin's 45th birthday. Compare their biological ages.



2. 1/ square root 1- v^2/c^2, My teacher is using v/c instead of giving me a velocity which is throwing me off, I'm not sure if I square the .98 or not.



3. 1/ square root 1- v^2/c^2, so what I was doing was putting the .98 and squaring it, which gives me .9604. I subtracted the 1 from .9604, and got .0396. I inverse the .0396 and get an answer of 25.25...Do I add that 25.25 to the original age of the astronaut which would give me an answer of 50.25 or is the astronauts age just 25.25...?
 
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Welcome to PF. We will not do your homework for you. Please show us your work, and discuss why you are unable to proceed. We will help by pointing you in the correction direction.

- Warren
 
i edited it chroot, is that better?
 
sorry i don't know how to use latex!
 
You're making this way too hard, I think.

Find gamma for v=0.98c. That's 1/Sqrt[1 - (0.98)^2].

The number of years elapsed onboard the spaceship is shorter than the time elapsed on Earth by a factor of gamma. So, the number of years elapsed on board the spaceship is 20/gamma.

- Warren
 
chroot said:
You're making this way too hard, I think.

Find gamma for v=0.98c. That's 1/Sqrt[1 - (0.98)^2].

The number of years elapsed onboard the spaceship is shorter than the time elapsed on Earth by a factor of gamma. So, the number of years elapsed on board the spaceship is 20/gamma.

- Warren

So i tried the formula you gave me (i was using the same one i thought but i got 50, i don't know what happen) and got an answer of 5.03. i don't understand your last part, the 20/gamma. since the 20 years elapsed, I'm dividing it by gamma= 5.03 and then do i add that to the astronauts original age giving him 30 years compared to his twin's 45th? this is just way too much for my understanding. sorry if I am being a pain
 
In the twenty years on earth, one twin's age increased by 20. Since he was 25 to begin with, he's 45 at the end of that time period.

In the same twenty of years on earth, the twin is flying around, and has aged only 5.03 years. The twin was also 25 when the experiment started, so now he's approximately 30 years old.

- Warren
 
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