I have a question about Calculating Avreage Speed

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To calculate the average speed of running a marathon backwards in both kilometers per hour and meters per second, first convert the time of 3 hours, 53 minutes, and 17 seconds into hours, resulting in approximately 3.298 hours. The formula for average speed is speed equals distance divided by time (v = d/t). Using the marathon distance of 42.2 kilometers, the average speed is calculated as 42.2 km divided by 3.298 hours, yielding about 12.8 km/h. To convert this speed into meters per second, divide by 3.6, resulting in approximately 3.55 m/s. The correct average speeds are 10.9 km/h and 3.01 m/s, indicating a need for accurate time conversion and calculation.
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The question states that Running a marathon backwards the record is 3 h 53 min 17 s and the race is 42.2 km's and I am supposed to calculate avreage speed of the race in meters per second and kilometres per hour I found a way to convert the record into just hours and I divided by 42.2 and the answer was completely wrong because according to the book its 10.9km/h and 3.01m/s does anyone have any idea how to achieve this answer?
 
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s=\frac{d}{t}
Speed is km/h, not h/km.
 
_wantana said:
The question states that Running a marathon backwards the record is 3 h 53 min 17 s and the race is 42.2 km's and I am supposed to calculate avreage speed of the race in meters per second and kilometres per hour I found a way to convert the record into just hours and I divided by 42.2 and the answer was completely wrong because according to the book its 10.9km/h and 3.01m/s does anyone have any idea how to achieve this answer?
Show your conversion of time to hour.
 
3 h 53min 17 s >3.29805556 hours
 
_wantana said:
3 h 53min 17 s >3.29805556 hours
Now v = d/t.
 
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