I know f=ma but I need velocity

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To find the other force acting on the particle moving at a constant velocity of v = (3 m/s)I - (4 m/s)j, it's essential to apply Newton's first law, which states that an object in motion remains in motion unless acted upon by a net external force. Given that the particle is moving at a constant velocity, the net force must be zero. The known force, F1 = (2 N)I + (-6 N)j, must be balanced by the other force, F2. Therefore, F2 can be calculated as F2 = -F1, resulting in F2 = (-2 N)I + (6 N)j. This ensures that the sum of the forces equals zero, maintaining the constant velocity of the particle.
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While two forces act on it a particle is to move at the constant velocity v= (3m/s)I - (4m/s)j. One of the forces is F1=(2n)I +(-6n)j what is the other force?


I want to say (1n)I + (2n)j but then I couldn't decided why that would be true. I guess I liked those numbers because if the mass were 1kg it would make the acceleration fit the requirements, I don't think I'm thinking about it correctly.
 
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Have a think about how Newtons first law would be applied to this situation.
 

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