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**1. The problem statement, all variables and given/known data**

A certain gas is at a temperature of 27 degrees Celcius. What would the temperature of the gas have to be to increase the rms speed of the molecules in the gas by 12 percent?

**2. Relevant equations**

V rms = √((3RT)/(M))

**3. The attempt at a solution**

We know R and T

R= 8.31 J/mol *k

New T= ?

M is unknown

T is what we must find.

V rms(.12) + 1 = ( Vrms1.12)

I don't know if I'm right but here's what I did.

3RT(2) = (1.12 Vrms)^ 2) * M

3RT(1) = (Vrms)^2) * M

We solve for T(2) or Temperature 2 or Temperature Final.

We divide (T2) over (T1)

3R cancels and M cancels

so we have T(2) / T(1) = 1.2544 Vrms ^2 / Vrms ^2

Vrms ^ 2 cancels

we are left with

T(2) = 1.2544 * T1

T(2) = 1.2544 * 27 degrees celcius = 33.8688

Is this correct.

Let's check if Vrms increases

T must increase and T did increase so I'm assuming that I did it right.

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