How Fast Must the Enterprise Travel to Shorten 85 Light Years to 20?

  • Thread starter Thread starter hype_chicky
  • Start date Start date
AI Thread Summary
To shorten the distance from 85 light years to 20 light years, the starship Enterprise must travel at a significant fraction of the speed of light. The relevant formula for this calculation is l = l0√(1 - (v/c)²), where l is the contracted length, l0 is the proper length, v is the velocity, and c is the speed of light. By applying this formula, one can solve for the required speed (v) to achieve the desired distance contraction. This question highlights the fascinating implications of relativity in space travel. Understanding these calculations is essential for theoretical discussions on interstellar travel.
hype_chicky
Messages
34
Reaction score
0
the starship enterprise wishes to fly a distant glaxy 85 light years away. At what speed would it have to travel in order that the distance tot he galaxy would only be 20 light years...RELAVITY:( ..help if u caaaan thank yous
 
Physics news on Phys.org
hmm

yes this is a rather intriguing question...i would love to see someone answer this one..any takers?
 
Have you seen the following formula:
l=l_{0}\sqrt{1-(v/c)^2}
You know both lengths and c, now just solve for v.
 
Last edited:
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top