# I need help with a basic physics problem!

## Homework Statement

A tennis ball is thrown from ground level with an initial velocity directed 30° above the horizontal. If it takes the ball 1 second to reach the top of its trajectory, what is the magnitude of the initial velocity?

## The Attempt at a Solution

I am new to physics and the only attempt I made towards this problem is a visual drawing of the problem. I do not understand what they mean by "what is the magnitude of the initial velocity?" Can someone please explain what I have to find here

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DaveC426913
Gold Member
"what is the magnitude of the initial velocity?"

It simply means 'What is the initial speed?'

Velocity is a vector, which means it is a magnitude (size) AND a direction (30 degrees from horiz). Speed is a scalar, which means it only has magnitude, not direction.

You simply need to worry about the initial speed, and not the initial direction.

Ok..... I understand what you told me and using what you told me my first gut reaction is to say that the answer is 0. Since the ball is not moving anywhere initially. Is this valid?

LowlyPion
Homework Helper
Ok..... I understand what you told me and using what you told me my first gut reaction is to say that the answer is 0. Since the ball is not moving anywhere initially. Is this valid?
No.

If it takes 1 second to reach the top then how high is that?

The ball has to have SOME initial speed greater than zero because it is travelling upwards. This is in the opposite direction to the acceleration due to gravity which is pulling the ball down and reducing the speed of the ball.

The maximum height that the ball reaches is when the ball has stopped travelling up and starts to fall back down because of gravity. Therefore, at time = 1 second, the ball's speed is momentarily zero.

Ok I have a feeling that the answer is 9.8m because once the ball is thrown in the air it automatically begins to decelerates because of gravity. Since it takes an object that was dropped to travel 9.8m in one second, an object that was thrown up and airborne for only one second must of been thrown up at an initial velocity of 9.8m/s as well because deceleration is -9.8m/s.

LowlyPion
Homework Helper
Ok I have a feeling that the answer is 9.8m because once the ball is thrown in the air it automatically begins to decelerates because of gravity. Since it takes an object that was dropped to travel 9.8m in one second, an object that was thrown up and airborne for only one second must of been thrown up at an initial velocity of 9.8m/s as well because deceleration is -9.8m/s.
That is correct ... except that he threw it at an angle of 30 degrees.

But the good news is you have calculated the initial y velocity. And at 30 degrees. you can know what the original velocity is by the y component being sin 30 degrees of the original velocity.