I think this is simple but I just cant work out how

  • Thread starter Thread starter oliver.smith8
  • Start date Start date
  • Tags Tags
    Work
AI Thread Summary
The discussion revolves around simplifying the expression \(\frac{1/a - 1/b}{1/a + 1/b}\) to show that it equals \(\frac{b-a}{b+a}\). Participants emphasize that the problem can be solved using basic algebraic manipulations. Key steps include rewriting the expression and multiplying both the numerator and denominator by \(ab\) to facilitate simplification. The goal is to demonstrate that the left-hand side can be transformed to match the right-hand side through these operations. Understanding these algebraic techniques is essential for solving the equation.
oliver.smith8
Messages
3
Reaction score
0
how does \frac{1/a -1/b}{1/a+1/b}= \frac{b-a}{b+a}

Ive been trying to work this out for ages

thanks
 
Physics news on Phys.org
It's simple algebra. Here's a few hints.

The right hand side, as given, is this:

\frac{\frac{1}{a} - \frac{1}{b}}{\frac{1}{a} + \frac{1}{b}}

But this can be written more clearly as:

(\frac{1}{a} - \frac{1}{b})(\frac{1}{a} + \frac{1}{b})^{-1}

From there, apply algebraic operations to this expression until it equals the right hand side.
 
Think about what value you need to multiply the left hand side with to make it equal the right hand side.
 
Multiply by ab in both the numerator and the denominator. This is multiplying by one.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top