I tried identifying the residue

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Homework Statement



how to compute the residue of 1/(cosh(z)^n) at z=ipi/2?

Homework Equations






b]3. The Attempt at a Solution [/b]
i tried to use cosh(z)=-isinh(z-ipi/2) and taylor expansion of this.then from expansion of 1/(1+z) and some algebraic manipulations i tried identifying the residue.it didn't really worked
 
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Sometimes it is helpful to go to the Laurent series to find the coefficient of the ##c_{-1}## term. In this case it is easier to find the order of the zero in the denominator by taking derivatives. Since there are no roots in the numerator, the order of the zero is the order of the pole.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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